(k^2-7k-18)/(6k+18)

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Solution for (k^2-7k-18)/(6k+18) equation: 


D( k )

6*k+18 = 0

6*k+18 = 0

6*k+18 = 0

6*k+18 = 0 // - 18

6*k = -18 // : 6

k = -18/6

k = -3

k in (-oo:-3) U (-3:+oo)

(k^2-(7*k)-18)/(6*k+18) = 0

(k^2-7*k-18)/(6*k+18) = 0

k^2-7*k-18 = 0

k^2-7*k-18 = 0

DELTA = (-7)^2-(-18*1*4)

DELTA = 121

DELTA > 0

k = (121^(1/2)+7)/(1*2) or k = (7-121^(1/2))/(1*2)

k = 9 or k = -2

(k+2)*(k-9) = 0

((k+2)*(k-9))/(6*k+18) = 0

( k+2 )

k+2 = 0 // - 2

k = -2

( k-9 )

k-9 = 0 // + 9

k = 9

k in { -2, 9 }

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